Add the integer parts from each term together.

$10+(−9)=1$

Use a Giant One to make the denominators of the fractions the same.

$\frac{7}{9}+\left(-\frac{2}{3}\right)\frac{3}{3}$

Simplify, reduce if possible. Then add the fraction sum to the integer sum.

$\frac{7}{9}+\left(-\frac{6}{9}\right)=\frac{1}{9}$

$1+\frac{1}{9}$

$1\frac{1}{9}$

Solve the same way that you solved part (a). Think about this problem as though you are adding negative numbers.

Change each number into a fraction greater than $1$.

$\left(\frac{9}{2}\right)\left(-\frac{33}{10}\right)$

Simplify, reduce if possible, and change answer into a mixed number if needed.

$-\frac{297}{20}=-14\frac{17}{20}$

Remember to multiply by the reciprocal.