CPM Homework Help : CCA2 Problem 4-68

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4-68.

Solve each equation below. Remember to check for extraneous solutions.

$(y−3)^2=2y−10$
Step 1(a):
Expand $(y−3)^2$ .
Step 2(a):
Set the equation equal to $0$ .
Step 3(a):
Factor and use the Zero Product Property or use the Quadratic Formula to solve.
Answer (a):
No real solutions.

$| y - 3 | = 2 y - 10$
Hint (b):
This equation has an absolute value, so you will need to write two equations to solve it.
Step 1(b):
$y−3=2y−10\ \text{or}\ y−3=−(2y−10)$
Possible solutions (b):
$y=7\text{ or }y=\frac{13}{3}$
Check both solutions in the original equation.
Do they both solve the equation?

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