$=\lim\limits_{a\to-\infty}\int_{a}^{-1}\frac{1}{\sqrt{2-x}}dx$

$=\left.\lim\limits_{a\to-\infty}\big(2-\sqrt{2-x}\big)\right|_{a}^{-1}$

$\lim\limits_{a\to -\infty}(2\sqrt{3}-2\sqrt{2-a})$

$\lim_\limits{b\to -\infty}\int_b^0 y^3dy+\lim\limits_{b\to \infty}\int_0^b y^3dy$

$\lim\limits_{c\to 0}\int_c^3\frac{1}{\sqrt{x}}dx$

$\operatorname{sec}(x)$ is undefined at $π/2$, so this integral will need to be split in two and limits used.

$\int\sec(x)dx=\ln\left|{\sec(x)+\tan(x)}\right|+C$