CPM Homework Help : CALC Problem 7-98

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7-98.

Integrate.

$\int _ { - 1 } ^ { 1 } 4 ^ { x + 2 } d x$
Hint (a):
Recall that $4^{x + 2} = (4^x)(4^2) = 16(4^x )$

$\int 6 t \cdot 7 ^ { 3 t ^ { 2 } } d t$
Hint (b):
$U$ −substitution
Step (b):
$=\int7^UdU$

$\int \operatorname { sin } ^ { 2 } ( 3 m - 1 ) \cdot \operatorname { cos } ( 3 m - 1 ) d m$
Step (c):
Let $U =\operatorname{sin}(3m − 1)$ .

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