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8-35.

Is there a in the interval for where ? Justify your answer.

If is continuous AND differentiable on the given domain, then the Mean Value Theorem will apply.

The Mean Value Theorem

The Mean Value Theorem for Integrals

If   is continuous on , then there exists at least one point  in  such that                     .

First quadrant, bell curve labeled, f of x, left end point on the y axis, labeled, a, right end point labeled, b, dashed horizontal segment, about 1 fourth up from x axis to peak, labeled average, & shaded rectangle between, A & b, segment & x axis, & circled points where the curve intersects the dashed segment, corresponding to tick marks on x axis, labeled, c subscript 1 & c subscript 2.

The Mean Value Theorem for Derivatives

If  is continuous on  and differentiable on , then there exists at least one point  in  such that .

Increasing curve labeled, capital F of x, starting at the origin, labeled a on the x axis, changing from concave up to concave down, in center of quadrant, ending at point corresponding to tick mark on x axis labeled, b, with dashed segment labeled, m = A R O C, from origin to end point, & 2 dashed parallel lines, one tangent before point of inflection, corresponding to tick mark on x axis labeled, c subscript 1, & one tangent after point of inflection, corresponding to tick mark on x axis labeled, c subscript 2.