CPM Homework Help : A2C Problem 1-49

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Home > A2C > Chapter Ch1 > Lesson 1.1.4 > Problem 1-49

1-49.

Solve each of the following quadratic equations. If you need help, refer to the Math Notes box for this lesson.

$x^2−8x+15=0$
Method 1(a):
Factor.
$(x−5)(x−3)=0$
Answer 1(a):
Use the Zero Product Property:
$(x−5)=0(x−3)=0\\ x=5x=3$
Method 2(a):
Use the Quadratic Formula.
$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(15)}}{2(1)}$
Answer 2(a):
$x=\frac{8\pm2}{2}$
$x=5,\,\,\,x=3$

$2x^2−5x−6=0$
Hint (b):
Notice if you try to factor $2x^2−5x−6$ , it doesn't work. Use the Quadratic Formula when that happens.
Answer (b):
$x=\frac{5\pm\sqrt{73}}{4}$
$x\approx3.39,\ x\approx-0.89$

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