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12-209.

If $p = \operatorname{ln} 2$ and $q = \operatorname{ln} 3$ , solve for $x i$ n terms of $p$ and/or $q$ .

$e^{x} = 2^{10}$
Step 1(a):
$x = \operatorname{ln}\left(2^{10}\right)$
Step 2(a):
$x = 10 \operatorname{ln}2$
Answer (a):
$x = 10p$

$4e^{x} = 27$
Hint (b):
See part (a).

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