CPM Homework Help : A2C Problem 6-11

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Home > A2C > Chapter Ch6 > Lesson 6.1.1 > Problem 6-11

6-11.

Solve each of the following equations for $x$ .

$\frac { x } { 3 } = \frac { 4 } { 5 }$
Answer (a):
$\textit{x}=\frac{12}{5}$

$\frac { x } { x + 1 } = \frac { 5 } { 7 }$
Answer (b):
$\textit{x}=\frac{5}{2}$

$\frac { 6 } { 15 } = 2 - \frac { x } { 5 }$
Hint (c):
Multiply both sides of the equation by $15$ .
$6 = 30 − 3x$

$\frac { 2 } { 3 } + \frac { x } { 5 } = 6$
Hint (d):
See part (c).

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