Begin by circling each term.

$\enclose{circle}{3}+\enclose{circle}{\:1\cdot4\:}+\enclose{circle}{\:(-7)\:}$

Simplify the expression.

$3+4+(-7)$
$7+(-7)=0$

$0$

Following the same steps as in part (a), try solving this problem before checking the answer.

$−20$

Follow the same steps as in part (a). Make sure you are circling the terms, so that simplifying is easier.

In this problem, make sure to add within the parentheses before multiplying for the final product.