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9-61.

Find the volume and surface area of a box with dimensions of $5\frac{1}{2}$ cm by $4\frac{1}{3}$ cm by $1\frac{1}{4}$ cm.

The volume of a box is (area of base) (height), or in this case (length) (width) (height).

The surface area of a box is the sum of the areas of its individual faces.

Remember to multiply mixed numbers, you must first convert them to fractions greater than one.

$\text{Volume}\ =\ 29\frac{19}{24}\;\text{cm}^3$
$\text{Surface Area}\ =\ 72\frac{1}{4}\;\text{cm}^2$