CPM Homework Help : ACC7 Problem 5-60

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Home > ACC7 > Chapter 5 Unit 3 > Lesson CC3: 5.2.4 > Problem 5-60

5-60.

Solve for $x$ .

$\frac { 2 } { 3 } = \frac { x } { 4 }$
Step 1 (a):
Multiply both sides by a common multiple of the denominators in order to get rid of the fractions.
Step 2 (a):
Divide both sides by $3$ to solve for $x$ .
$8=3x$
Answer (a):
$x = \frac{8}{3}$

$\frac { 2 } { 3 } = \frac { x } { 4 } + \frac { x } { 3 }$
Step 1 (b):
Multiply both sides by a common multiple of the denominators in order to get rid of the fractions.
$8=3x+4x$
Step 2 (b):
Combine like terms.
$8=7x$
Step 3 (b):
Divide both sides by $7$ to solve for $x$ .
Answer (b):
$x=\frac{8}{7}$

How are these problems the same and how are they different?
Hint (c):
What did you do different in part (b)?

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