$3\left(2x\right) − 3\left(1\right) + 2y = 5x$ Distribute.
$6x − 3 + 2y = 5x$

$-6x -6x$ Subtract 6x from both sides.
$−3 + 2− = −x$

$+3 +3$ Add $3$ to both sides
$2y = -x + 3$

Divide both sides by $2$.

${\it y} = \frac{-{\it x} + 3}{2}$

Follow the same method as in part (a).