Substitute $16$ into the equation for $x$.

$\small y=3+\sqrt[3]{16-8}$

Do the subtraction inside the root.

$\small y=3+\sqrt[3]{8}$

Find the cube root.
$y=3+2$
Add.

$y=5$

Use the same method as part (a) to find the answer.

Substitute $16$ into the equation for $x$, then do the subtraction inside the absolute value symbols before adding