### Home > CCAA8 > Chapter 11 Unit 12 > Lesson CCA: 11.2.1 > Problem11-35

11-35.

Fully investigate the function $g(x)=\sqrt{x-3}+1$.

Where is the starting point of the function?
What is the lowest/highest value of $x$ you can have?
What is the lowest/highest value of $g(x)$ you can have?
Is this function linear?
Is it increasing or decreasing?

The function starts at $(3,1)$.
The domain (possible values of $x$) is $x\ge3$.
The range (possible values of $g(x)$) is $g(x)\ge1$.

Use the eTool below to help investigate the function.
Click on the link at right for the full eTool version: