Home > CCAA8 > Chapter 4 Unit 5 > Lesson CCA: 4.3.1 > Problem4-98

4-98.

Find the point of intersection for each set of equations below using any method. Check your solutions, if possible.

1.  \begin{aligned}[t] 6x &- 2y = 10 \\ 3x &- 5 = y \end{aligned}

Substitution is one way to solve this system.
$6x-2(3x-5)=10$:

Distribute the left side.
$6x-6x+10=10$

Combine like terms.
$10=10$

All numbers

1.  \begin{aligned}[t] 6x &- 2y = 5 \\ 3x &+ 2y = -2 \end{aligned}

Elimination is one method to solve this system.

$\left(\frac{1}{3},-\frac{3}{2}\right)$

1.  \begin{aligned}[t] 5 &- y = 3x \\ y &= 2x \end{aligned}

1.  \begin{aligned}[t] y &= \frac{1}{4}x + 5 \\ y &= 2x - 9 \end{aligned}