CPM Homework Help : CCAA8 Problem 5-107

CPM Homework Banner

Home > CCAA8 > Chapter 5 Unit 6 > Lesson CCA: 5.3.2 > Problem 5-107

5-107.

Solve each equation.

$(x+2)(x+3)=x^2-10$
Hint (a):
Rewrite the left side. Then isolate $x$ .
Answer (a):
$x=-\frac{16}{5}$

$\frac { 1 } { 2 } x + \frac { 1 } { 3 } x - 7 = \frac { 5 } { 6 } x$
Hint(b):
Multiply all terms by $6$ (including the $7$ ), then solve.

$| 2 x - 1 | = 9$
Hint (c):
Note the absolute value sign. You will need to solve two equations:
$2x − 1 = 9$ and $2x − 1 = −9$

$\frac { x + 1 } { 3 } = \frac { x } { 2 }$
Answer (d):
$x = 2$

© 2022 CPM Educational Program. All rights reserved.