### Home > CCAA8 > Chapter 6 Unit 7 > Lesson CCA: 6.1.4 > Problem6-38

6-38.

If $f ( x ) = \frac { 1 } { x + 2 }$, find each of the following values.

1.  $f(−3)$

• Evaluate the fraction when x = –3.

1.  $f(−1.5)$

• $f(-1.5)=\frac{1}{-1.5+2}$

• $f(-1.5)=\frac{1}{0.5}$

1.  $f(−2)$

• Undefined.
Since evaluating the function at −2 results in a zero in the denominator, the function is undefined at x = −2.

1.  $x \text{ if }f(x)=5$

• $\text{Solve the equation 5 = }\frac{1}{\textit{x}+2}.$