### Home > CCAA8 > Chapter 6 Unit 7 > Lesson CCA: 6.2.5 > Problem6-119

6-119.

If $g ( x ) = \sqrt { x - 3 } + 1$, find the values below. If there is no solution, justify your conclusion.

1. $g(7)$

Substitute 7 into the equation.

$g(7) = \sqrt{7 - 3} + 1$

$g(7) = \sqrt{4} + 1$

g(7) = 2 + 1

g(7) = 3

1. $g(4)$

$g(4) = 2$

1. $g(8)$

1. $g(2)$

Can you take the square root of a negative number?