### Home > GB8I > Chapter 11 Unit 12 > Lesson INT1: 11.2.3 > Problem11-77

11-77.

Mr. Greer solved an equation below. However, when he checked his solution, it did not make the original equation true. Find his error and then find the correct solution.

\begin{aligned}[t] 4x &= 8\left(2x - 3\right) \\ 4x &= 16x - 3 \\ -12x &= -3 \\ x &= \frac{-3}{-12} \\ x &= \frac{1}{4} \end{aligned}

Check Mr. Greer's distribution. Did he do it correctly?

Is $8$ times $-3$ equal to $-3$?

Solve the equation by distributing correctly.