### Home > GB8I > Chapter 5 Unit 6 > Lesson INT1: 5.3.2 > Problem5-110

5-110.

Solve each equation.

Review the Math Notes box in Lesson 1.3.2 for the laws of exponents.

1. $( x + 2 ) ( x + 3 ) = x ^ { 2 } - 10$

1. $\frac { 1 } { 2 } x + \frac { 1 } { 3 } x - 7 = \frac { 5 } { 6 } x$

no solution

1. $\quad \frac { x + 1 } { 3 } = \frac { x } { 2 }$

Multiplying both sides by $6$ will 'bust the fraction'.

1. $9 ^ { x } = ( \frac { 1 } { 3 } ) ^ { x + 3 }$

$3^2$ can be substituted for the $9$.

$3^{-1}$ can be substituted for $\frac{1}{3}$

$\left (3^{2} \right )^{x}=\left ( 3^{-1} \right )^{x+3}$