### Home > GB8I > Chapter 7 Unit 8 > Lesson INT1: 7.1.2 > Problem7-27

7-27.

Solve each system.

Read Math Notes box in Lesson 6.2.3 on the substitution method.

1. $6x − 2y = 10$
$3x − 2 = y$

There is no solution.

1. $3x − 9y = 3$
$2x = 16 − y$

Solve the lower equation for $y$, and then substitute the expression for $y$ into the top equation and solve.

1. $y = 3x + 1$
$x + 2y = −5$

Substitute $3x + 1$ for y in the second equation.

$(−1, −2)$

1. $2x + 3y = 9$
$x − 2y = 1$

Multiply the entire second equation by $−2$

Add the equations together.

$(3, 1)$