### Home > CCA2 > Chapter Ch11 > Lesson 11.2.1 > Problem11-46

11-46.

Solve the system below.

$\frac{z+y}{4}+\frac{z-y}{2}=1$

$\frac{3z-y}{4}+\frac{4z+2y}{11}=3$

Eliminate the denominators in both equations and simplify them before solving.

$4\left(\frac{z +y}{4}+\frac{z - y}{2} = 1\right)$

$44\left(\frac{3z-y}{4}+\frac{4z+2y}{11} = 3\right)$

$(z + y) + 2(z - y) = 4$

$11(3z - y) + 4(4z + 2y) = 132$

$3z - y = 4$

$54z - 3y = 132$

Now finish solving this system of equations.