CPM Homework Help : CCA2 Problem 4-95

Solve the equations below.

Step 1(a):

Square both sides.

$\left(\sqrt{x+15}\right)^2=\left(5+\sqrt{x}\right)^2$

$x+15=\left(5+\sqrt{x}\right)\left(5+\sqrt{x}\right)$

$x+15=25+10\sqrt{x}+x$

Step 2(a):

Isolate the square root of $x$ on one side of the equation.

$-10=10\sqrt{x}$

Step 3(a):

Divide both sides by $10$ .

$-1=\sqrt{x}$

Hint (a):

What can you take the square root of and get $−1$ ?

Answer (a):

No real solutions.

Step 1(b):

Expand the $(y−6)^2$ .

Step 2(b):

Rearrange the equation so that it equals zero.

Step 3(b):

Solve by factoring and using the Zero Product Property, or use the Quadratic Formula.