### Home > CC1 > Chapter 8 > Lesson 8.1.4 > Problem8-55

8-55.

Use the Distributive Property to rewrite each expression below. Then evaluate each expression for $y = 3$ and $z = 4$.

1. $2y^2-5y$

Think of this expression as $(y·2y)-(y·5)$.

Using the Distributive Property, the expression becomes
$y(2y-5)$. When $3$ is substituted for y, the expression becomes $3(2·3-5)=3(6-5)=3$

1. $3(8-2z)$

Think of the expression as $3·8-3·2z$.

The expression becomes $24-6z$. Now substitute $4$ for $z$.

1. $5z^2-15z$

Both numbers and variables can be factored out together. Solve this one like you did part (a).

1. $4y+6z$

Be careful with the variables. Remember that because the variables are different, they cannot be factored out. However, there is a number that can be factored out.