### Home > CC2 > Chapter 6 > Lesson 6.2.3 > Problem6-87

6-87.

1. $5(x-2)+(-9)=-7(1-x)$

Distribute the $5$ and $-7$, respectively. Remember that the $7$ is negative so the signs inside the parentheses need to change.

$5x-10+(-9)=-7+7x$

Isolate $x$ on one side of the equation.

$-12=2x$

Solve for $x$ using division.

$x=-6$

1. $-6x-7=-1(-9+2x)$

Follow the steps outlined in part (a). Start by distributing $-1$ on the right side of the equation.