CPM Homework Help : CC3 Problem 3-27

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3-27.

Calculate the following values using the Order of Operations. Show your steps. Verify your answers with your calculator.

$(-4)(-2)-6(2-5)$
Step 1 (a):
Circle the terms. $\enclose{circle}[mathcolor="blue"]{\color{black}{\left(-4\right)\left(-2\right)}}-\enclose{circle}[mathcolor="blue"]{\color{black}{6\left(2-5\right)}}$ The negative 4 times negative two is circled. and the 6 times 2 minus 5 is circled.
Step 2 (a):
Simplify within the circled terms. $8-6(-3)$
Step 3 (a):
Circle the terms again. Then simplify and repeat. $\enclose{circle}[mathcolor="blue"]{\color{black}{8}}-\enclose{circle}[mathcolor="blue"]{\color{black}{6\left(-3\right)}}$ Circle the 8 and the 6 times negative 3.

$23-(17-3·4)^2+6$
Hint (b), (c), (d):
For parts (b), (c), and (d) follow the strategy outlined in part (a).

$14(2+3-2·2)\div(4^2-3^2)$
Answer (c):
$2$

$12.7-18.5+15+6.3-1+28.5$

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