CPM Homework Help : CC3 Problem 6-38

Solve the system of equations below using the Equal Values Method.

$a=12b+3$
$a=-2b-4$

Hint:

Set the two equations equal to each other.
$12b+3=-2b-4$

More Help 1:

Solve for $b$ .
$14b=-7$

Answer 1:

$b=-\frac{1}{2}$

More Help 2:

Substitute $b$ back into one of the original equations to find $a$ .
$a=12\left(-\frac{1}{2}\right)+3$
$a=-6+3$

Answer 2:

Remember to check by substituting $a$ and $b$ back into both of the original equations.
$a=-3$