Home > CC3 > Chapter 6 > Lesson 6.1.4 > Problem6-38

6-38.

Solve the system of equations below using the Equal Values Method. Homework Help ✎

$a=12b+3$
$a=−2b−4$

Set the two equations equal to each other.

Solve for $b$.

$12b+3=−2b−4$

$14b=−7$

$b= -\frac{1}{2}$

Substitute $b$ back into one of the original equations to find $a$.

Remember to check by substituting $a$ and $b$ back into both of the original equations.

$a= 12\left(-\frac{1}{2}\right)+3$

$a=−6+3$

$a=−3$