CPM Homework Help : CCA Problem 11-35

Fully investigate the function $g(x)=\sqrt{x-3}+1$ .

Hint:

Where is the starting point of the function?
What is the lowest/highest value of $x$ you can have?
What is the lowest/highest value of $g(x)$ you can have?
Is this function linear?
Is it increasing or decreasing?

Answer:

The function starts at $(3,1)$ .
The domain (possible values of $x$ ) is $x\ge3$ .
The range (possible values of $g(x)$ ) is $g(x)\ge1$ .

Use the eTool below to help investigate the function.
Click on the link at right for the full eTool version: 11-35 HW eTool