Evaluate the fraction when x = –3.

$f(-1.5)=\frac{1}{-1.5+2}$

$f(-1.5)=\frac{1}{0.5}$

Undefined.
Since evaluating the function at −2 results in a zero in the denominator, the function is undefined at x = −2.

$\text{Solve the equation 5 = }\frac{1}{\textit{x}+2}.$