CPM Homework Help : CCA Problem 6-87

Here is an alternative way to define a recursive sequence.

$\begin{array} l a_1=5\\a_n=a_{n−1}+6\end{array}$

Therefore: $\begin{array}[t]{l}a_1=5\\a_2=a_1+6=5+6=11\\a_3=a_2+6=11+6=17\end{array}$

Now continue the sequence:

$a_4=a_?+\:?=\:?$
Hint (a):
$\textit{a}_{4} \; =\; \textit{a}_{3} + 6 = ?$
Answer (a):
$\textit{a}_{4} \;=\;23$
$a_5=a_?+\:?=\:?$
Hint (b):
See part (a).
The first 5 terms of the sequence are:
Hint (c):
See parts (a) and (b).