### Home > CCA > Chapter 6 > Lesson 6.2.3 > Problem6-87

6-87.

Here is an alternative way to define a recursive sequence.

 $a_1=5$ $a_n=a_{n−1}+6$ Therefore:  $a_1=5$                    $a^2=a_1+6=5+6=11$                    $a_3=a_2+6=11+6=17$

Now continue the sequence: Homework Help ✎

1. $a_4=a_?+\:?=\:?$

$\textit{a}_{4} \; =\; \textit{a}_{3} + 6 = ?$

$\textit{a}_{4} \;=\;23$

2. $a_5=a_?+\:?=\:?$

See part (a).

3. The first 5 terms of the sequence are:

See parts (a) and (b).