CPM Homework Help : CCA2 Problem 10-56

Solve:

log_{$_7$} $(3x-2)=2$
Hint (a):
Rewrite the equation in exponential form.
Step (a):
$7^2 = 3x − 2$

$2^x ⋅ 2^{x-2} - 16^2 = 0$
Step 1(b):
$2^{2x-2}= 16^2$
Step 2(b):
$2^{2x - 2} = (2^4)^2$