Home > CCA2 > Chapter 10 > Lesson 10.1.4 > Problem10-68

10-68.

Graph each plane in three dimensions. Homework Help ✎

1. $2x - 3y + 4z = 12$

Solve for each intercept. You can do this by substituting $0$ for two of the variables and solving for the remaining variable.

$2x - 3(0) + 4(0) = 12$
$2x = 12$
$x = 6$
$(6, 0, 0)$

$2(0) - 3y + 4(0) = 12$
$-3y = 12$
$y = -4$
$(0, -4, 0)$

$2(0) - 3(0) + 4z = 12$
$4z = 12$
$z = 3$
$(0, 0, 3)$

Now that you know the $x-$, $y-$, and $z$-intercepts, plot the points, connect them, and shade them to look like a plane.

1. $2x − 3y = 12$

Solve for the intercepts like you did in part (a).
Note that there is no $z$-intercept.