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Home > CCA2 > Chapter 10 > Lesson 10.3.1 > Problem 10-149

10-149.
  1. Donna has four bracelets in her jewelry box. They can all be worn together, but each is different from the others. Before she goes to bed at night, she sets out the outfit she will wear the next day, including her accessories. How many different ways can she choose the following: 0 bracelets? 1 bracelet? 2 bracelets? 3 bracelets? 4 bracelets? Homework Help ✎

    1. How do these possible combinations compare to the 4th row (n = 4) of Pascal’s Triangle?

    2. If Donna bought two new bracelets, how many combinations of four bracelets can she choose for her outfit? How can you figure this out without multiplying or using your calculator?

4C0, 4C1, 4C2, etc.

How do the numerical values of the answer to the original problem compare to the 4th row of Pascal's Triangle?

Use Pascal's Triangle. Which row?