Multiply both equations by a common denominator to remove the fractions.
$4\left(\frac{x}{2}+\frac{y}{4}\right)=\left(4\right)4$
$8\left(\frac{x}{4}-\frac{3y}{8}\right)=\left(-2\right)8$
$2x+y=16$
$2x-3y=−16$

Solve the new system of equations using the Elimination Method.

$4y=32$, so $y=8$.
Substitute this value back into one of the original equations to solve for $x$.

$(4,8)$

Simplify this system of equations using substitution.

Start by solving the third equation for $z$.
$z = \frac{-3y}{2}$

Substitute this value into the first two equations and simplify.
$4x +\frac{y}{2}=-1$
$x + \frac{y}{2}=-1$

You can now solve this equation using the Elimination Method as in part (a).