### Home > CCA2 > Chapter 12 > Lesson 12.2.2 > Problem12-122

12-122.

Solve for $x$, correct to three decimal places.

1. $27 = 6^x$

How do you ''undo'' an exponent?
What do you have to do to both sides of the equation?

1. $27 =\frac { 1 } { 6 ^ { x } }$

Rearrange the equation so that the term with the exponent is no longer in the denominator.

$x ≈ −1.839$

1. $27=\frac { 1 } { \large{\left( \frac { 1 } { 6 } \right)} ^ { x } }$

This is the same as part (a). Why?

$x ≈ 1.839$

1. Show that $\frac { 1 } { \large{\left( \frac { 1 } { 6 } \right)} ^ { x } }= 6^x$

This is similar to part (c), but you already have the answer!