### Home > CCA2 > Chapter 2 > Lesson 2.2.3 > Problem2-128

2-128.

For each equation below, find the x- and y-intercepts and the locator point (h, k), then write the equations in graphing form. Homework Help ✎

1. $y=7+2x^2+4x-5$

y-intercept: $y=7+2(0)^2+4(0)−5$

x-intercept: $0=7+2x^2+4x−5$

Since there is only one x-intercept, the vertex must be at the x-intercept.

y-intercept: (0, 2)
x-intercept: (−1, 0)
vertex: (−1, 0)
$y=2(x+1)^2$

2. $x^2=2x+x(2x-4)+y$

Start by finding the x- and y-intercepts.

To find the x-coordinate of the vertex,
average the x-intercepts.

To find the y-coordinate of the vertex, substitute the
x-coordinate of the vertex into the given equation and solve for y.

Now write the equation in graphing form.