Explain completely how to get a good sketch of the graph of
but shift the graph 6 units to the left and 7 units down.
Explain how to change the graph from part (a) to represent the graph of
It would move up 9 units.
Given the original graph, how can you get the graph of
into the new, absolute value equation and into the original. How do the outputs differ?
All the points that had negative y-values will now have positive y-values.
Restrict the domain of the original parabola to
and graph its inverse function.
The inverse function is now an
parabola with its vertex at . For the inverse, . Why?
What would be the equation for the inverse function if you restricted the domain to
and in the original equation and solve for .
Use the eTool below to explore the graphs needed to solve the parts of the problem.
Click the link to the right for full version. CCA2 5-80 HW eTool