Convert both inequalities into equations and simplify into graphing form.

$y=2x^2+1$

A parabola with vertex at $(0,1)$ and vertically stretched by $2$.

$1+x−y=3x−2y−4\\y=2x−5$

A line with slope $2$ and $y$-intercept $(0,−5)$.

Graph both equations, then test points to find which area is the solution to the system of inequalities.