### Home > CCA2 > Chapter 7 > Lesson 7.1.4 > Problem7-68

7-68.

Solve each equation.

1. $\frac { 3 } { x + 1 } = \frac { 4 } { x }$

Multiply both sides of the equation by $x\left(x + 1\right)$.

$x = −4$

1. $\frac { 3 } { x + 1 } + \frac { 4 } { x } = 2$

See part (a).

1. $\frac { 3 } { x + 2 } + 5 = \frac { 3 } { x + 2 }$

Look at the equation carefully before you try to solve it.

no solution

1. Explain why part (c) has no solution.

Substitute $\:a = \frac{3}{x + 2}$