CPM Homework Help : CCA2 Problem 7-68

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Home > CCA2 > Chapter 7 > Lesson 7.1.4 > Problem 7-68

7-68.

Solve each equation.

$\frac { 3 } { x + 1 } = \frac { 4 } { x }$
Hint (a):
Multiply both sides of the equation by $x\left(x + 1\right)$ .
Answer (a):
$x = −4$

$\frac { 3 } { x + 1 } + \frac { 4 } { x } = 2$
Hint (b):
See part (a).

$\frac { 3 } { x + 2 } + 5 = \frac { 3 } { x + 2 }$
Hint (c):
Look at the equation carefully before you try to solve it.
Answer (c):
no solution

Explain why part (c) has no solution.
Hint (d):
Substitute $\:a = \frac{3}{x + 2}$

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