On graph paper, graph the parabola $y=2x^2-5x-3$.  

1. What are the roots ($x\text{-intercepts}$) of the parabola?

   Hint (a):

   Look at the graph. Where does the parabola cross the $x\text{-axis}$?

2. Read the Math Notes box for this lesson. Then solve the equation $2x^2-5x-3=0$ algebraically. Did your solutions match your roots from part (a)?

   Hint (b):

   Use the Quadratic Formula.

   Answer (b):

   One solution is $x=\large\frac{-(-5)+\sqrt{(-5)^{2}-4(2)(-3)}}{2(2)}$ , or $x=3$.