### Home > CCG > Chapter 4 > Lesson 4.2.1 > Problem4-62

4-62.

Solve each equation to find the value of $x$. Leave your answers in decimal form accurate to the thousandths place.

When solving equations with an $x^2\text{-term}$, you can use the Quadratic Formula.

1. $\frac { 3.2 } { x } = \frac { 7.5 } { x ^ { 2 } }$

$3.2x^2=7.5x$

1. $4(x-2)+3(-x+4)=-2(x-3)$

$4x-8+(-3x)+12=-2x+6$

1. $2x^2+7x-15=0$

One solution is $x=1.5$

1. $3x^2−2x=−1$

To use the Quadratic Formula, the equation must be in the form $ax^2+bx+c=0$.

No real solution.