CPM Homework Help : CCG Problem 5-42

Find the equation of the line that has a $33.7^\circ$ slope angle and a $y$ -intercept at $(0,7)$ . Assume the line has a positive slope.

Hint 1:

Sketch a graph and a slope triangle for the line.

A second quadrant graph of a slope triangle. The slope angle is 33.7 degrees. A point on the line is (0, comma 7).

Hint 2:

$Δx=?$
$Δy=7$

Use the tangent ratio to find the slope:

$\frac{\Delta y}{\Delta x}=\text{slope} = \text{tan}(\theta)$

Hint 3:

Once you know the slope and the $y$ -intercept, you can write the equation of the line. You use slope-intercept form $(y=mx+b)$ .

Answer:

$y \approx \frac{2}{3}x + 7$