Plot $ΔABC$ on graph paper with points $A(3,3)$, $B(1,1)$, and $C(6,1)$.  

1. Transform $ΔABC$ by multiplying the y-coordinates of the vertices by  $-1$. Then use the function $(x,y)→(x-6,y-3)$ to translate the resulting triangle. Name the coordinates of the vertices of the result.

   Step 1(a):

   Multiply all of the $y\text{-coordinates}$ of the vertices by $-1$. What transformation happens to the triangle?

   Step 2(a):

   In the translation rule the $x-6$ means to move to the left $6$, and the $y-3$ means to move down $3$. List the final coordinates of the vertices of the new triangle.

2. Rotate $ΔABC$ $90^{\circ}$ counterclockwise $(\circlearrowleft)$ about the origin. Then reflect the result across the $y$-axis. Name the coordinates of the vertices of the result.

   Hint (b):

   What are the coordinates of the vertices of the final figure?

   Answer (b):

   $A''(3,3)$, $B''(1,1)$, $C''(1,6)$