Notice the inequality symbols. f(2) exists as part of the right side of f(x) not the left.
f(2) = 2(2)+3 = 7
Compare this question to part (a).
Compare this question to part (a). Even though f(2) does not exist in the left side of the equation, since both sides approach x = 2 we can evaluate what it approaches.
x →2−, y →(2)²−1 or y →3
Is f(x) continuous at x = 2? In other words, does f(x) approach the same y-value from the left and from the right of x = 2?