### Home > CALC3RD > Chapter Ch9 > Lesson 9.2.1 > Problem9-56

9-56.

No calculator! A particle’s position as function of time is defined as $x(t) = 2t$ and $y(t) = \sqrt { t + 3 }+ 1$ . Create a table for $-3 ≤ t ≤ 3$ and carefully graph the situation.

$\left. \begin{array} { | c | c | c | } \hline t & { x = 2 t } & { y = \sqrt { t + 3 } + 1 } \\ \hline - 3 & { - 6 } & { 1 } \\ \hline - 2 & { - 4 } & { 2 } \\ \hline - 1 & { } \\ \hline 0 \\ \hline 1 \\ { 1 } \\ { 2 } \\ { 3 } \\ \hline \end{array} \right.$

Complete the table. Then be sure to graph the $(x, y)$ points.