Home > CALC3RD > Chapter Ch9 > Lesson 9.4.3 > Problem9-131

9-131.

What is $\frac { d } { d x } \int _ { 4 } ^ { 6 x ^ { 2 } - 2 } ( 9 \sqrt { t - 1 } ) d t$?

You will need to use the Chain Rule.

Let $a = 4$ and $b = 6x^2 - 2$.

$(9\sqrt{b-1})(b^\prime)-(9\sqrt{a-1})(a^\prime)$