### Home > INT1 > Chapter Ch11 > Lesson 11.1.1 > Problem11-8

11-8.

Solve each equation. Check your solutions, if possible.

1. $8a + a - 3 = 6a - 2a - 3$

Isolate the variable on one side of the equation, with the integers on the other side.

1. $8(3m - 2) - 7m = 0$

Distribute before solving the equation.

1. $\frac{x}{2}+1=6$

Multiply each term of the equation by 2 in order to cancel out the fraction.

1. $|x-3|+5=11$

There are two solutions to this equation. Why?