### Home > APCALC > Chapter 1 > Lesson 1.3.1 > Problem1-103

1-103.

Multiple Choice: The values of $x$ for which the graphs of $y = x + 3$ and $y^2 = 6x$ intersect are: Homework Help ✎

1. $−3$ and $3$

2. $−3$

3. $3$

4. $0$

5. None of these

Solve the equation $y = x + 3$ for $x$.

Does this equation have any solutions?

Substitute this value into the second equation. $y^² = 6(y − 3)$

Set this equation equal to $0$. $y^² − 6y + 18 = 0$