### Home > APCALC > Chapter 1 > Lesson 1.4.4 > Problem1-189

1-189.

Let $g(x)=(3x-1)^2$.

1. What is $g(–5)$?

$g(−5) = 256$

2. Write an expression for $g(a + 1)$ and simplify.

Substitute $(a + 1)$ for $x$. Simplify.

3. If $g(x) = 49$, what are the possible values of $x$?

Set $(3x - 1)²$ equal to $49$ and solve for $x$.

4. Write an equation for $g^{–1}(x)$.

Let $g(x) = y$. Solve for $x$. Then switch the $x$ and $y$.

Remember the $±$.