### Home > APCALC > Chapter 10 > Lesson 10.1.1 > Problem10-9

10-9.

Multiple Choice: The equation of the line tangent to the curve $3x^2y - 2x = y^2$ at the point $(1, 1)$ is: Homework Help ✎

1. $y = -4x + 1$

1. $y = -4x + 5$

1. $y =\frac { 1 } { 2 }x + 1$

1. $y = \frac { 1 } { 2 }x+\frac { 1 } { 2 }$

1. none of these

$6xy+3x^2y^\prime-2=2yy^\prime$

$6(1)(1)+3(1)^2y^\prime-2=2(1)y^\prime$

Solve for $y^\prime$. This is the slope of the line.